SOLUTION: Express the confidence interval in the form of P ± E. 15) -0.128 < p < 1.212

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Question 313892: Express the confidence interval in the form of P ± E.

15) -0.128 < p < 1.212


Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
Express the confidence interval in the form of P ± E.

-0.128 < p < 1.212 

First find the mean value (average) P of -0.128 and 1.212

%28-0.128%2B1.212%29%2F2=1.084%2F2=0.542

Then the difference between the mean value P and the lower value

0.542-%28-0.128%29=0.542%2B0.128=0.67

is the same as the difference between the upper value and the 
mean value

1.212-0.542=0.67

and this value is the "Error", E.

Thus in the form P ± E, the answer is

0.542 ± 0.67

Edwin