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Question 313871: Graph the triangle enclosed by the Y-axis and the graphs of y - 3x = -2 and y + 3x = 2 Find the area of the triangle.
Found 2 solutions by solver91311, Edwin McCravy:
Answer by solver91311(24713)   (Show Source):
You can put this solution on YOUR website!
Substitute 0 for  , then  , hence  -intercept is ) .
Substitute 0 for , then  , hence -intercept is ) .
Substitute 0 for , then  , hence -intercept is ) .
Substitute 0 for , then , hence -intercept is . Note that this is the same as the -intercept for the first equation, hence it is the point of intersection of the two lines represented by the two equations and therefore the third vertex of the triangle.
The other two vertexes are the -intercepts of the two equations. The base of the triangle is therefore that segment of the -axis between the two intercept points, while the altitude of the triangle is the segment between the origin and the point of intersection of the two lines.
You can either use the distance formula:
^2\ +\ (y_1\ -\ y_2)^2})
or simple inspection to determine that the measure of the base of the triangle is 4 and the measure of the altitude is  .
Use these values in the formula for the area of a triangle:
where  represents the measure of the base and  represents the measure of the height or altitude.
John
Answer by Edwin McCravy(20056)  (Show Source):
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