SOLUTION: Fifty-six percent of American adults eat at a table-service restautant at least once a week. Suppose that four American adults are askedif they ate at table-service restaurants las
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Question 313847: Fifty-six percent of American adults eat at a table-service restautant at least once a week. Suppose that four American adults are askedif they ate at table-service restaurants last week. What is the probability that all of them say yes? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Fifty-six percent of American adults eat at a table-service restautant at least once a week. Suppose that four American adults are askedif they ate at table-service restaurants last week. What is the probability that all of them say yes?
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P(4 yes) = (0.56)^4 = 0.0983
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Cheers,
Stan H.
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