SOLUTION: factor completely 4x^2-28xy+49y^2
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Question 31382
:
factor completely
4x^2-28xy+49y^2
Answer by
mukhopadhyay(490)
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4x^2-28xy+49y^2
=(2x)^2-28xy+(7y)^2
=(2x)^2-2.2x.7y+(7y)^2
=(2x-7y)^2
(