Question 313737: A company owns 400 laptops. Each laptop has an 8% probability of not working. You randomly select 20 laptops for your salespeople.
A) What is the likelihood that 5 will be broken?
B) What is the likelihood that they will all work?
C) what is the likelihood that they will all be broken?
Thank you,Jen
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! A company owns 400 laptops. Each laptop has an 8% probability of not working. You randomly select 20 laptops for your salespeople.
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Binomial Problem with n = 20 and p = 0.08
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A) What is the likelihood that 5 will be broken?
P(x = 5) = 20C5*0.08^5*0.92^15 = binompdf(20,0.08,5) = 0.0145
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B) What is the likelihood that they will all work?
Ans: 0.92^20 = 0.1887
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C) what is the likelihood that they will all be broken?
Ans: 0.08^20 = 1.1529x10^-22
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Cheers,
Stan H.
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