Question 313731: 16y^5 - 24y^4 - 40y^3
I'm stuck...this is what I came up with:
4y^5 - 6y^4 - 10y^3
Should I be breaking it down again?
Answer by rapaljer(4671)   (Show Source):
You can put this solution on YOUR website! First look for COMMON FACTORS. In this case, the common factor is 8y^3
16y^5-24y^4-40y^3
8y^3(2y^2-3y-5)
Now factor the trinomial:
8y^3(2y-5)(y+1)
If you have trouble FACTORING, then you probably need to see my own website for all the FREE resources that I have there, including my OWN explanation of Factoring. To see my website, click on my tutor name "Rapaljer" anywhere in algebra.com. On my information page, click on the link to my website. Look for the link on my Homepage "Basic, Intermediate, and College Algebra: One Step at a Time." Choose "Basic Algebra", then "Chapter 2", for the topics about factoring. The first step in your problem here is called "Factoring the Common Factor." The second step is called "Advanced Trinomial Factoring." This is my OWN non-traditional explanation, complete with examples, exercises, and ALL of the answers, that my own students found much easier to understand than the regular textbooks. See also my "Math in Living Color" pages that go with this section. In these pages, I explain the solutions to many of the exercises IN LIVING COLOR!!
See also the videos, made from my own classes a few years ago before I retired. These videos are now available FREE on my website. From my Homepage, look for the link "Rapalje Vidoes in Living Color", then look in either Basic Algebra or Intermediate Algebra for the topic on "Factoring."
Dr. Robert J. Rapalje, Retired
Seminole State College of Florida
Altamonte Springs Campus
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