Question 313664: For a particular event, 812 tickets were sold for a total of $1912. If students paid $2 per ticket and non-students paid $3 per ticket, how many student tickets were sold?
I am having a problem just setting up the initial equation. I think I am over analyzing this problem.
I've tried 2t + 3t = 812; I have tried 2t + 3t = 1048
I've went on to the harder problems for my assignment and had no problem finding my solutions. This is a stumper for me.
Thank you in advance for your attention to my brain freeze.
Jennifer
Answer by texttutoring(324)   (Show Source):
You can put this solution on YOUR website! Define your variables:
Let x=number of student tickets
Let y = number of non-student tickets
There are two unknowns, so you need two equations.
Equation 1: x+y=812
Equation 2: 2x + 3y = 1912
Isolate for x or y in Equation 1, and substitute it into Equation 2:
y=812-x
2x +3(812-x)=1912
2x +2436 - 3x = 1912
-x = -524
x = 524
You can then use equation 1 or 2 to find y.
812-x = y
812-524 = y
y =288
There were 524 student tickets sold, and 288 non-student tickets.
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