SOLUTION: Solve the following application problem (show your equation and then your solution). Round answers to nearest thousandths and properly label your answer as well.
A rectangular ga
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-> SOLUTION: Solve the following application problem (show your equation and then your solution). Round answers to nearest thousandths and properly label your answer as well.
A rectangular ga
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Question 313614: Solve the following application problem (show your equation and then your solution). Round answers to nearest thousandths and properly label your answer as well.
A rectangular garden is to be surrounded by a walkway of constant width. The garden's dimensions are 15ft by 25ft. The total area, garden plus walkway, is to be 650ft^2. What must be the width of the walkway? Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! (15+2X)(25+2X)=650
375+50X+30X+4X^2=650
4X^2+80X+375-650=0
4X^2+80X-275=0
X=(-80+-SQRT[80^2-4*4*-275])/2*4
X=(-80+-SQRT[6,400+4,400])/8
X=(-80+-SQRT10,800)/8
X=(-80+-103.923)/8
X=(-80+103.923)/8
X=23.923/8
X=2.99 ANS. FOR THE WIDTH OF THE WALKWAY.
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