SOLUTION: Solve the following application problem (show your equation and then your solution). Round answers to nearest thousandths and properly label your answer as well. The length of a

Algebra ->  Rectangles -> SOLUTION: Solve the following application problem (show your equation and then your solution). Round answers to nearest thousandths and properly label your answer as well. The length of a       Log On


   

Question 313613: Solve the following application problem (show your equation and then your solution). Round answers to nearest thousandths and properly label your answer as well.
The length of a rectagle is 2 cm. more than 3 times its width. If the area of the rectange is 95 cm^2, find the dimensions of the rectangle.
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
L=3W+2
A=LW
95=(3W+2)W
95=3W^2+2W
3W^2+2W-95=0
W+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
W=(-2+-SQRT[2^2-4*3*-95])/2*3
W=(-2+-SQRT[4+1,140])/6
W=(-2+-SQRT1,144)/6
W=(-2+-33.823)/6
W=(-2+33.823)/6
W=31.823/6
W=5.304 ANS.
W=(-2-33.823)/6
W=-35.823/6
W=-5.967 ANS.