SOLUTION: how do you find a logarithm set say the question is 7^4x-13=343?

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Question 313485: how do you find a logarithm set say the question is
7^4x-13=343?
Found 2 solutions by nyc_function, nerdybill:
Answer by nyc_function(2741) About Me  (Show Source):
You can put this solution on YOUR website!
Are you looking for x?
If so, 434 = 7^3.
7^(4x - 13) = 7^(3)
Since we now have the same base 7 on both sides, bring down and equate all exponents.
4x - 13 = 3
4x = 3 + 13
4x = 16
x = 16/4
x = 4
Is this what you need?

Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
I think you mean:
7%5E%284x-13%29+=+343+
If not, please write back...
.
7%5E%284x-13%29+=+343+
4x-13+=+log%287%2C343%29+
4x+=+log%287%2C343%29+%2B+13+
x+=+%28log%287%2C343%29+%2B+13%29%2F4+
x+=+%28log%287%2C7%5E3%29+%2B+13%29%2F4+
x+=+%283+%2B+13%29%2F4+
x+=+16%2F4+
x+=+4+