SOLUTION: 3 outside of square root of 27/64? 10/y=3/5? (2x^2+3x-6)+(x^2-18x+6)

Algebra ->  Square-cubic-other-roots -> SOLUTION: 3 outside of square root of 27/64? 10/y=3/5? (2x^2+3x-6)+(x^2-18x+6)      Log On


   

Question 313479: 3 outside of square root of 27/64? 10/y=3/5? (2x^2+3x-6)+(x^2-18x+6)
Answer by JBarnum(2146) About Me  (Show Source):
You can put this solution on YOUR website!
3rd rt of (27/64)=?
27=3%5E3
64=4%5E3
3rd rt of 3%5E3%2F4%5E3=highlight%283%2F4%29
ok
10%2Fy=3%2F5 cross multiply
5%2A10=3y
50=3y
highlight%2850%2F3=y%29
ok
%282x%5E2%2B3x-6%29%2B%28x%5E2-18x%2B6%29 add like terms
2x%5E2%2Bx%5E2%2B3x-18x%2B6-6
3x%5E2-15x factor out 3x
highlight%283x%28x-5%29%29
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