SOLUTION: Three times the first of three consecutive numbers is four more than two times the second. 3x=2(x+1)+4 3x=2(x+2)+4 3x=2(x+3)+4 is this how I would set it up?

Algebra ->  Customizable Word Problem Solvers  -> Numbers -> SOLUTION: Three times the first of three consecutive numbers is four more than two times the second. 3x=2(x+1)+4 3x=2(x+2)+4 3x=2(x+3)+4 is this how I would set it up?      Log On

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Question 313399: Three times the first of three consecutive numbers is four more than two times the second.
3x=2(x+1)+4
3x=2(x+2)+4
3x=2(x+3)+4 is this how I would set it up?

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Which equation? You have 3 of them.
One of them is correct.
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First, identify your variables.
x - first number
x%2B1 - 1st consecutive number, second number
x%2B2 - 2nd consecutive number, third number
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3*First=4+2*Second
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3x=4%2B2%2A%28x%2B1%29