Question 31328: I need help on practical questions relating to chi-squared distribution:-
60 male and 50 female students at school. Each had to choose after-school activity from football,tennis,badmington and athletics. 25 males and 10 females picked football, only 3 males decided on tennis and 14 for badmington. Rest of males chose athletics along with 30 females. Remainder of females chose tennis and badminton in equal measure.
a)write down observed and expected frequency tables
b)write down null and alternative hypothesis to test wether sex and activity related
c)carry out chi squared distribution test at 5% significance level to test above hypothesis
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! You get two rows: male and female:
Columns left to right are football, tennis, badminton, athletics
Observed values for males are 25, 3, 14, 18 to total 60
Observed values for girls are 10, 5, 5, 30 to total 50
Expected values follow the formula (row total)(column total)/(grand total)
So corresponding to the "25" box you have (60)(35)/110= 19.09
Do that for each of the eight boxes to get all the expected values.
The null hypothesis is "The rows are homogeneous"
The altermate is "The rows are not homogeneous".
Using a TI-83 Chi-Sq. Test I get Chi-Sq.= 13.3933...
and p=0.003
Since 0.003<5% we reject the null hypothesis and conclude
that sex does play a factor in what games people choose
to sign up for.
Cheers,
Stan H.
Since
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