SOLUTION: Given 4 red balls, 3 yellow, and 5 blue, select two balls. What is the probability that you select one red ball and one yellow ball, without replacement? 4/12 * 2/11= 2/33

Algebra ->  Probability-and-statistics -> SOLUTION: Given 4 red balls, 3 yellow, and 5 blue, select two balls. What is the probability that you select one red ball and one yellow ball, without replacement? 4/12 * 2/11= 2/33      Log On


   

Question 313213: Given 4 red balls, 3 yellow, and 5 blue, select two balls. What is the probability that you select one red ball and one yellow ball, without replacement?

4/12 * 2/11= 2/33
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
P(R)=4/12=1/3
With one R ball out, ball count goes down 1.
P(Y)=3/11
P(R,Y)=(1/3)(3/11)=1/11