Question 313207: The perimeter of a rectangle is 224 inches. The length exceeds the width by 52 inches. Find the length and the width. Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! L=W+52
P=2L+2W
224=2(W+52)+2W
224=2W+104+2W
4W=104-224
4W=120
W=120/4
W=30 ANS. FOR THE WIDTH.
L=30+52=82 ANS. FOR THE LENGTH.
PROOF:
224=2*82+2*30
224=164+60
224=224