SOLUTION: At 3:15p.m., Jim had cross country skied 4mi. By 4:05p.m., he had skied 10mi. Find his average rate of travel.

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Question 313172: At 3:15p.m., Jim had cross country skied 4mi. By 4:05p.m., he had skied 10mi. Find his average rate of travel.
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
He covered 6 miles in 50 minutes (5%2F6 hour).
Speed*Time=Distance
Speed=Distance/Time
S=6%2F%285%2F6%29=36%2F5=7.2 mph