Question 313057: An object's altitude, in meters, is given by the polynomial h + vt - 9.8t2, where h is the height in meters from which the launch occurs, v is the initial upward speed in meters per second, and t is the number of seconds for which the rocket is airborne. A pebble is shot upward from the top of a building 150 meters tall. If the initial speed is 35 meters per second, how high above the ground will the pebble be after 3 seconds?
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! An object's altitude, in meters, is given by the polynomial h + vt - 9.8t^2, where
h is the height in meters from which the launch occurs, v is the initial upward
speed in meters per second, and t is the number of seconds for which the rocket
is airborne.
A pebble is shot upward from the top of a building 200 meters tall.
If the initial speed is 30 meters per second, how high above the ground will the pebble be after 4 seconds?
:
f(t) = height of pebble in t seconds
The equation
f(t) = -9.8t^2 + 30t + 200
t = 4 sec
f(4) = -9.8(4^2) + 30(4) + 200
f(4) = -9.8(16) + 120 + 200
f(4) = 156.8 + 120 + 200
f(4) = 163.2 m after 4 sec
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