SOLUTION: What are the Real zeros for f(x) = x^3+2x^2-4

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Question 312985: What are the Real zeros for f(x) = x^3+2x^2-4
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
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I used Newton's method,
x(n+1)=x(n)-f(x(n))/f'(x(n))
with a starting value of x0=1 and got a value of x=1.130395 after 3 iterations.