Question 312929: find sin 0 if cos 0=-2/3 and 90 degree<0>180 degrees
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! find sin(w) if cos(w) = -2/3 and 90 degree< w <180 degrees
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By definition cos(w) = x/r
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Since cos(w) = -2/3, x = -2 and r = 3
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r^2 = x^2 + y^2
9 = (-2)^2 + y^2
y = sqrt(5)
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By definition sin(x) = y/r
Ans: sin(x) = sqrt(5)/3
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Cheers,
Stan H.
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