SOLUTION: joe has a total of $580 consisting 5$ and 10$ bills. If he has 76 bills in all, how many of each type does he have?

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Question 312857: joe has a total of $580 consisting 5$ and 10$ bills. If he has 76 bills in all, how many of each type does he have?


Found 2 solutions by stanbon, rfer:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
joe has a total of $580 consisting 5$ and 10$ bills. If he has 76 bills in all, how many of each type does he have?
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Quantity Equation: f + t = 76
Value Equation::: 5f+10t = 580
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Solving by elimination:
Multiply thru the 1st equation by 5 to get:
5f + 5t = 5*76
5f +10t = 580
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Subtract 1st from 2nd and solve for "t":
5t = 200
t = 40 (# of ten-dollar bills)
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Since f+t=76, f = 76-40 = 36 (# of five-dollar bills)
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Cheers,
Stan H.

Answer by rfer(16322) About Me  (Show Source):
You can put this solution on YOUR website!
f+t=76 t=76-f
5f+10(76-f)=580
5f+760-10f=580
-5f=-180
f=36 fives
t=76-36
t=40 tens
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400+180=580