SOLUTION: {{{x^3+3x^2+10x-8/3x^2+7x-6=}}}

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: {{{x^3+3x^2+10x-8/3x^2+7x-6=}}}      Log On


   

Question 312530: x%5E3%2B3x%5E2%2B10x-8%2F3x%5E2%2B7x-6=
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
%28x%5E3%2B3x%5E2%2B10x-8%29%2F%283x%5E2%2B7x-6%29
In order to get x%5E3 multiply 3x%5E2%2B7x-6 by %281%2F3%29x to get x%5E3%2B%287%2F3%29x%5E2-2x.
Subtract that from the original polynomial to get a remainder of,
%28x%5E3%2B3x%5E2%2B10x-8%29-%28x%5E3%2B%287%2F3%29x%5E2-2x%29=%282%2F3%29x%5E2%2B12x-8.
Multiply 3x%5E2%2B7x-6 by %282%2F9%29 to get %282%2F3%29x%5E2%2B%2814%2F9%29x-4%2F3, subtract from the remainder to get the new remainder,

No further division can occur,