SOLUTION: Please help! I am lost in how to figure this out: f(x)= -2x^2+2x+8 This one has several parts.. The x coordinate of the vertex? The y coordinate of the vertex? The e

Algebra ->  Linear-equations -> SOLUTION: Please help! I am lost in how to figure this out: f(x)= -2x^2+2x+8 This one has several parts.. The x coordinate of the vertex? The y coordinate of the vertex? The e      Log On


   



Question 312383: Please help! I am lost in how to figure this out:
f(x)= -2x^2+2x+8
This one has several parts..
The x coordinate of the vertex?
The y coordinate of the vertex?
The equation of the line of symmetry?
The maximum/minimum of f(x)?
Is the value of f(1/2)=17/2 maximum or minimum?
Thanks!

Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
Please help! I am lost in how to figure this out:
%22f%28x%29%22=+-2x%5E2%2B2x%2B8

That's the same as

y+=+-2x%5E2%2B2x%2B8

Plot some points:

(-2,-4), (-1,4), (0,8), (1,8), (2,4), (3,-4)

and get this graph:

graph%28200%2C400%2C-3%2C4%2C-5%2C9%2C+-2x%5E2%2B2x%2B8%29

This one has several parts..
The x coordinate of the vertex?

Learn the formula:

The x-coordinate of f%28x%29=Ax%5E2%2BBx%2BC is -B%2F%282A%29

Compare
%22f%28x%29%22=+-2x%5E2%2B2x%2B8
to
%22f%28x%29%22=+Ax%5E2%2BBx%2BC

and observe that A=-2, B=2, C=8

Then substitute and get

-B%2F%282A%29=-2%2F%282%2A%28-2%29%29=-2%2F%28-4%29=1%2F2%29

The y coordinate of the vertex?

Learn the rule: To get the y-coordinate of the vertex,
after finding the x-coordinate of the vertex, substitute
the value of the x-coordinate of the vertex x in the original 
equation:

%22f%28x%29%22=+-2x%5E2%2B2x%2B8
f%281%2F2%29=+-2%281%2F2%29%5E2%2B2%281%2F2%29%2B8
f%281%2F2%29=+-2%281%2F4%29%2B1%2B8
f%281%2F2%29=+-1%2F2%2B9
f%281%2F2%29=-1%2F2%2B18%2F2=17%2F2=8%261%2F2

So the y coordinate of the vertex is 17%2F2 or 8%261%2F2

That makes the vertes (1%2F2,8%261%2F2), or (0.5,8.5)

and we see that looks right according to the graph:




The equation of the line of symmetry?

Learn the rule that the equation of the line of symmetry
is always the vertical line whose equation is

x = the x-coordinate of the vertex

So the axis of symmetry has the equation 

x+=+1%2F2 or x=0.5

which is a vertical line 1%2F2 a unit right of the y-axis
and parallel to it (vertical), and when we graph it (in green,



and we see that this vertical line whose equation is x=1%2F2,
bisects the parabola. 

The maximum/minimum of f(x)?

Learn that the maximum or minimum value is the y-coordinate of
the vertex.

The maximum or minimum point is the same as the vertex.

To determine whether or not it is a maximum or a minimum
we need to know whether the parabola opens upward or downward.
To determine this we look at the coefficient of x%5E2.
If it is positive then the parabola opens upward and the
vertex is a minimum point. If it is negative, the parabola 
opens downward and the vertex is a maximum.  

%22f%28x%29%22=+-2x%5E2%2B2x%2B8

Here we see that the coefficient of x%5E2 is negative and
that the parabola opens downward, so the vertex is a maximum.
We knew it opened downward because we graphed it, but we
would have known it opened downward even if we had not
graphed it because the coefficient of x%5E2 is negative. 


Is the value of f%281%2F2%29=17%2F2 maximum or minimum?

It is a maximum as we have just seen.
Thanks!