SOLUTION: hey i really need help in this problem it is really hard.. my problemis 3k^2-39k+90 i don't now what signes to use and how do i get the answer. i really need help i have a quiz tom
Algebra ->
Polynomials-and-rational-expressions
-> SOLUTION: hey i really need help in this problem it is really hard.. my problemis 3k^2-39k+90 i don't now what signes to use and how do i get the answer. i really need help i have a quiz tom
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Question 31224This question is from textbook ALGEBRA 1 CONCEPTS AND SKILLS
: hey i really need help in this problem it is really hard.. my problemis 3k^2-39k+90 i don't now what signes to use and how do i get the answer. i really need help i have a quiz tomorrow and i don't want to fail it please help me understand this! thank you This question is from textbook ALGEBRA 1 CONCEPTS AND SKILLS
You can put this solution on YOUR website! hey i really need help in this problem it is really hard.. my problemis 3k^2-39k+90 i don't now what signes to use and how do i get the answer. i really need help i have a quiz tomorrow and i don't want to fail it please help me understand this! thank you
WHAT DO YOU WANT ?FATORISE?IF SO....
3K^2-39K+90=3(K^2-13K+30).....FIND PRODUCT OF COEFFICIENTS OF K^2 AND CONSTANT TERMS =1*30=30
FIND 2 FACTORS FOR THIS 30 SO THAT THEIR SUM = COEFFICIENT OF X TERM =-13
30=1*30=2*15=3*10=(-3)*(-10)....SUM OF -3 AND -10 = -13..SO WRITE AS FOLLOWS
3(K^2-3K-10K+30)=3{K(K-3)-10(K-3)}=3(K-3)(K-10)
