SOLUTION: log2/log3.log3/log4.log4/log5.........log15/log16

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Question 312070: log2/log3.log3/log4.log4/log5.........log15/log16
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


What does this mean? Are you trying to multiply a series of factors each consisting of some log divided by some other log?


John