Question 311863: How do you solve this word problem concerning interest?
Gilbert invested part of his $10,000 bonus in a CD that paid 6% interest, and the rest in a fund that paid 11% interest. If his total interest was $900, how much did Gilbert invest in the fund?
Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! .11x+.06(10,000-x)=900
.11x+600-.06x=900
.05x=900-600
.05x=300
x=300/.05
x=6,000 invested @ 11%.
10,000-6,000=4,000 invested @ 6%
Proof:
.11*6,000+.06*4,000=900
660+240=900
900=900
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