SOLUTION: Question 1-Etch Clean Graphics uses one cleanser
that is 25% acid and a second that is 50% acid. How
many liters of each should be mixed to get 10 L of a
solution that is
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-> SOLUTION: Question 1-Etch Clean Graphics uses one cleanser
that is 25% acid and a second that is 50% acid. How
many liters of each should be mixed to get 10 L of a
solution that is
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Question 311660: Question 1-Etch Clean Graphics uses one cleanser
that is 25% acid and a second that is 50% acid. How
many liters of each should be mixed to get 10 L of a
solution that is 40% acid?
Question 2-Automotive Maintenance. "Arctic Antifreeze" is 18% alcohol and "Frost No-More" is 10% alcohol. How many liters of Arctic Antifreeze should be mixed with 7.5 L of Frost No-More in order to get a mixture that is 15% alcohol?
You can put this solution on YOUR website! Question 1-Etch Clean Graphics uses one cleanser
that is 25% acid and a second that is 50% acid. How
many liters of each should be mixed to get 10 L of a
solution that is 40% acid?
.
cleanser A 25% acid - x liters
cleanser B 50% acid -10-x liters
Total 10 liters 40%
.
Concentration of A +concentration of B = Total concentration of mixture
0.25x+0.5(10-x)=0.4*10
0.25x+5-0.5x=4
-0.25x=-1
x=-1/-0.25
x=4 liters 25% & 6 liters 50%
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Question 2-Automotive Maintenance. "Arctic Antifreeze" is 18% alcohol and "Frost No-More" is 10% alcohol. How many liters of Arctic Antifreeze should be mixed with 7.5 L of Frost No-More in order to get a mixture that is 15% alcohol?
..
arctic antifreeze 18% - x liters
Frost no-more 10%, 7.5 liters
Total x+7.5 liters , 15%
.
0.18x+0.1*7.5 = 0.15(x+7.5)
0.18x+0.75=0.15x+1.125
0.18x-0.15x=1.125-0.75
0.03x=0.375
x=0.375/0.03
x=12.5 liters
CHECK
(0.18*12.5)+(0.1*7.5)=3
