SOLUTION: A boxing ring is in the shape of a square, 20 feet on each side. How far apart are the fighters when they are in opposite corners of the ring?
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-> SOLUTION: A boxing ring is in the shape of a square, 20 feet on each side. How far apart are the fighters when they are in opposite corners of the ring?
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Question 311647: A boxing ring is in the shape of a square, 20 feet on each side. How far apart are the fighters when they are in opposite corners of the ring? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A boxing ring is in the shape of a square, 20 feet on each side. How far apart are the fighters when they are in opposite corners of the ring?
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Draw the picture.
Draw a line from corner to opposite corner.
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The corner to corner line is the hypotenuse of a right triangle.
Use Pythagoras to find the length of the hypotenuse.
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h^2 = 20^2 + 20^2
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h^2 = 2*20^2
h = 20sqrt(2)feet
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Cheers,
Stan H.
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