SOLUTION: Gary is standing on a dock 2.0m above the water. He is pulling in a boat that is attached to the end of a 5.2 m rope. If he pulls in 2.3 m of rope, how far did he move the boat?

Click here to see ALL problems on Length-and-distance

Question 311625: Gary is standing on a dock 2.0m above the water. He is pulling in a boat that is attached to the end of a 5.2 m rope. If he pulls in 2.3 m of rope, how far did he move the boat?
Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website!
Garys height above water = 2 meters.( vertical height)
rope tied to a boat = 5.2 meters.( hypotenuse)
sqrt ((5.2)^2 -(2)^2) = distance of boat from foot of the dock
=4.8 meters
..
the rope is pulled in by 2.3 meters.
Now the rope's length to the boat = 2.9 meter.
this is the hypotenuse.
.
vertical height = 2 meters.
sqrt ((2.9)^2-(2)^2)= 2.1
Now the boat is 2.1 meters from the foot of the dock.
The boat has moved from 4.8 meters to 2.1 meters from the foot of the dock
So he has moved the boat by 2.7 meters.