SOLUTION: 25-[2+5y-3(y+2)]=-3(2y-5)-[5(y-1)-3y+3]

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Question 31158This question is from textbook college algebra
: 25-[2+5y-3(y+2)]=-3(2y-5)-[5(y-1)-3y+3] This question is from textbook college algebra

Answer by gymnast2598(2) About Me  (Show Source):
You can put this solution on YOUR website!
25-[2+5y-3(y+2)]=-3(2y-5)-[5(y-1)-3y+3]
↑ ↑ ↑
distribute the -3 and 5
25-2+5y-3y-6=-6y+15-5y-5-3y+3
↑ ↑
combine all variables
17+2y=8-14y
↑ ↑←←←←←←←←←←←←←←
subtract seventeen from here ↑
2y=-9-14y
↑←←←←←←←←←
add 14y to here↑
16y = -9