SOLUTION: A handful of 65 coins consist of pennies, nickles, and dimes. The number of nickels is 4 less than twice the number of pennies, and there are 13 more dimes than nickles. how many c
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Question 311542: A handful of 65 coins consist of pennies, nickles, and dimes. The number of nickels is 4 less than twice the number of pennies, and there are 13 more dimes than nickles. how many coins of each kind are there?
You can put this solution on YOUR website! n=2p-4
d=n+13 or d=(2p-4+13)
p+n+d=65
p+(2p-4)+(2p-4+13)=65
5p-4-4+13=65
5p=65+4+4-13
5p=60
p=60/5
p=12 pennies.
n=2*12-4
n=24-4=20 nickles.
d=20+13=33 dimes.
Proof:
12+20+33=65
65=65
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