Question 311444: Hi, My name is Gary Baldwin and I am having trouble setting up this word problem. I am suppose to set it up into 2 linear equations and solve them. OK, here is the problem: Two programmers are working on writing a new program that will check for viruses when incoming messages enter the company’s server. The first programmer, Sammy, plans to mark up the price of his virus program by 35%, whereas the second programmer, Martin, plans to mark up the price of his virus program by 54%. If Sammy’s program sells for $285 and Martin’s program sells for $325, who originally had the cheaper program before the price markup.
Thank you in advance for your help
Sincerely,
Gary Baldwin
Found 2 solutions by rfer, Miceandwine:
Answer by rfer(16322)   (Show Source):
Answer by Miceandwine(15) (Show Source):
You can put this solution on YOUR website! Hey there Gary! I believe I can try to help you. Let's get started.
Well, first off, lets get the prices of the original software. I always find questions out like this in what I consider the most simple way:
(original price)(Percent of price)=(changed price)
So how I would set up one of your problems is
(x)(1.35)=(285) the reason why it is 1.35 is because it is 135% of the original price, by the way.
Then, I divide the 1.35 from both sides so the problem looks like this:
x=211.11.
So the original price of Sammy's software is $211.11. Let's move on.
Now, we'll just do the same thing for Martin.
(x)(1.54)=325 and then divide so:
x=211.04
So Sammy's is just a couple cents more expensive than Martin's!
I guess a way to make this into a linear equation would be to have the y intercept be the original price and the slope would be the percent increase, but I'm not so sure on that part. I'm so sorry!
I hope this helped you a bit!
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