SOLUTION: Stever can tape and mud the drywall of a room in 6 hours. Mike can do it in 4 hours. Mike joins Steve an hour after Steve starts and together they worked finishing the job. How l
Algebra ->
Rate-of-work-word-problems
-> SOLUTION: Stever can tape and mud the drywall of a room in 6 hours. Mike can do it in 4 hours. Mike joins Steve an hour after Steve starts and together they worked finishing the job. How l
Log On
Question 311314: Stever can tape and mud the drywall of a room in 6 hours. Mike can do it in 4 hours. Mike joins Steve an hour after Steve starts and together they worked finishing the job. How long did each one work? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Steve can tape and mud the drywall of a room in 6 hours.
Mike can do it in 4 hours.
Mike joins Steve an hour after Steve starts and together they worked finishing the job.
How long did each one work?
:
Let t = Mikes working time
then
(t+1) = Steve's working time
:
Let the completed job = 1
:
A shared work equation + = 1
multiply equation by 12, results
2(t+1) + 3t = 12
:
2t + 2 + 3t = 12
:
2t + 3t = 12 - 2
:
5t = 10
t =
t = 2 hrs is Mike's working time
and
2 + 1 = 3 hrs is Steve's working time
:
:
Check solution + = 1
