SOLUTION: Hi I am getting ready to take the TEAS test and I am a little rusty on algebra so your help would be greatly appreciated. Problem: If Sally can paint a house in 4 hours, and Ji

Algebra ->  Rate-of-work-word-problems -> SOLUTION: Hi I am getting ready to take the TEAS test and I am a little rusty on algebra so your help would be greatly appreciated. Problem: If Sally can paint a house in 4 hours, and Ji      Log On


   



Question 31127: Hi I am getting ready to take the TEAS test and I am a little rusty on algebra so your help would be greatly appreciated.
Problem: If Sally can paint a house in 4 hours, and Jim can paint the same house in 6
hours, how long would it take to paint the house if they paint together?

Answer by mbarugel(146) About Me  (Show Source):
You can put this solution on YOUR website!
Hello!
Please see my lesson on this kind of problems.
If Sally can paint the house in 4 hours, then she paints 1/4 of the house per hour.
If Jim can paint the house in 6 hours, then he paints 1/6 of the house per hour.
Therefore, when working together, their rate of work is 1%2F4%2B1%2F6+=+5%2F12 of the house per hour. Since they paint 5/12 of the house per hour, then they need 12/5, or 2.4 hours to paint the house together.

I hope this helps!
Get more answers at Online Math Answers.com!