SOLUTION: Solve 8x^2 + 2x - 3 = 0 Reduce fractions to lowest terms. a) x = 3/4 or x = -3/4 b) x = 2 or x = -3 c) x = 1/2 or x = -3/4 d) x = 3/4 or x = -1/2

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Solve 8x^2 + 2x - 3 = 0 Reduce fractions to lowest terms. a) x = 3/4 or x = -3/4 b) x = 2 or x = -3 c) x = 1/2 or x = -3/4 d) x = 3/4 or x = -1/2       Log On


   

Question 311103: Solve 8x^2 + 2x - 3 = 0 Reduce fractions to lowest terms.
a) x = 3/4 or x = -3/4
b) x = 2 or x = -3
c) x = 1/2 or x = -3/4
d) x = 3/4 or x = -1/2
Answer by Miceandwine(15) About Me  (Show Source):
You can put this solution on YOUR website!
Solve 8x^2 + 2x - 3 = 0 Reduce fractions to lowest terms.
a) x = 3/4 or x = -3/4
b) x = 2 or x = -3
c) x = 1/2 or x = -3/4
d) x = 3/4 or x = -1/2
Okay, so for this all we need is a bit of factoring!
so we should first multiply 8 by -3. The answer is -24. Then, all you have to do is find the two factors of that number that will create the middle number. Those numbers are -4 and 6. So now it is time for equations!
(8x^2-4x) (6x-3) Now take out the common factors.
4x(2x-1) 3(2x-1) Now put those all together
(4x+3)(2x-1)=0 Now you have to find the number that makes at least one of the expressions equal to ZERO
4x+3=0
4x=-3
x=-3/4
and for the other equation:
2x-1=0
2x=1
x=1/2
So the answer is C.
I hope this helped!