SOLUTION: rewrite as a single logarithm: 2ln4x+ln2x-ln5x Solve: 2+log3(6x)=5

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Question 310923: rewrite as a single logarithm:
2ln4x+ln2x-ln5x
Solve: 2+log3(6x)=5
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
2ln4x%2Bln2x-ln5x
ln%284x%29%5E2%2Bln2x-ln5x
ln16x%5E2%2Bln2x-ln5x
ln16x%5E2%282x%29-ln5x
ln%2832x%5E3-ln5x%29
ln%2832x%5E3%2F5x%29
ln%2832x%5E2%2F5%29

Solve: 2+log3(6x)=5
I'll assume you meant log base 3:
2%2Blog%283%2C6x%29=5
log%283%2C6x%29=3
6x+=+3%5E3
6x+=+27
x+=+27%2F6
x+=+9%2F2