SOLUTION: Question: if 2x-4y=-2 and 3x-2y=3, then 2y+x= I need help solvng one equation in terms of the other to answer this question. thanks

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Question 31090: Question: if 2x-4y=-2 and 3x-2y=3, then 2y+x=
I need help solvng one equation in terms of the other to answer this question.
thanks
Found 2 solutions by Cintchr, ikdeep:
Answer by Cintchr(481) About Me  (Show Source):
You can put this solution on YOUR website!
+2x-4y=-2+ and +3x-2y=3+ then +2y%2Bx=z+
Using the first equation ... solve for x
+2x-4y=-2+
+2x=4y-2+ divide all parts by 2
+x=2y-1+ substitute this value into the 2nd equation
+3x-2y=3+
+3%282y-1%29-2y=3+ solve for y
+6y-3-2y=3+
+4y-3=3+
+4y=6
+y=6%2F4+ or +y=3%2F2+ substitute this back into the first eq.
+x=2y-1+
+x=2%283%2F2%29-1+ solve for x
+x=3-1+
+x=2+ substitute x and y into the third equation
+2y%2Bx=z+ and +x=2+ and +y=3%2F2+
+2%283%2F2%29+%2B+2+=z+
+3+%2B+2+=z+
+5+=+z+

Answer by ikdeep(226) About Me  (Show Source):
You can put this solution on YOUR website!
2x-4y= -2...............(1)
3x-2y=3 .................(2)....
we solve the above equations by elimination method ...
multiply (1)by 3 and (2)by 2..we get
6x - 12y = -6..............(3)
6x - 4y = 6 .................(4)
Subtract (4) from(3)..we get
6x - 12y = -6..............(3)
6x - 4y = 6 .................(4)
- + -
----------------
- 8y = -12
y = -12/-8
y = 3/2
putting the values of y in any of the equation to get the value of x ,,,here i am taking equation (1)..we get
2x-4y= -2...............(1)
2x-(4*3)/2=
solving the brackets,, we get ...
2x-12/2= -2
2x-6 = -2
add 6 on both sides and we get
2x = -2 +6
solving RHS ,,we get
2x = 4
divide both sides by 2 ,,we get
x = 2
Now if you want to verify you answer ,,,you can put the values of x and y in any of the equation and if you get LHS=RHS,,,this means that you answer is correct..
now to find the value of ...
2y+x=
put the values of x and y from above,,,,,and we get
2y+x= 2(3/2) + 2
2y+x= 3 + 2
2y+x= 5.........
hope this will help you
Please feel free to revert back for any further queries.