SOLUTION: Steve's first aquarium had a rectangular base that was 8 inches longer than it was wide. He replaced this with a larger aquarium that was 2 inches wider and 4 inches longer than t

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Question 31078: Steve's first aquarium had a rectangular base that was 8 inches longer than it was wide. He replaced this with a larger aquarium that was 2 inches wider and 4 inches longer than the first one. He found that if he filled each to a depth of 10 inches, it required 840 cubic inches more water to fill the new aquarium than the old. What were the dimensions of the base of the original aquarium?
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
(X+(X+8)*10+840=(X+2)(X+12)*10 OR (X~2+8X)*10+840=(X~2+14X+24)*10 OR
10X~2+80X+840=10X~2+140X+240 OR 840-240=140X-80X OR 600=60X OR X=600/60 OR X=10
PROOF (10*18)*10+840=(12*22)*10 OR 180*10+840=264*10 OR 1800+840=2640 OR
2640=2640
THE ORIGINAL DIMENTION WAS 10 AND 18 INCHES