SOLUTION: Find four consecutive odd integers if the product of the two smaller integers is 112 less than the product of the two larger integers.

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: Find four consecutive odd integers if the product of the two smaller integers is 112 less than the product of the two larger integers.      Log On


   

Question 310746: Find four consecutive odd integers if the product of the two smaller integers is 112 less than the product of the two larger integers.
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
N, N%2B2, N%2B4, N%2B6 are the odd integers.
.
.
.
N%28N%2B2%29=%28N%2B4%29%28N%2B6%29-112
N%5E2%2B2N=N%5E2%2B6N%2B4N%2B24-112
2N=10N-88
-8N=-88
N=11
11,13,15,17 are the integers.