SOLUTION: Find 3 consecutive odd numbers where the product of the smaller two numbers is 34 less than the square of the largest number.

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Question 310737: Find 3 consecutive odd numbers where the product of the smaller two numbers is 34 less than the square of the largest number.
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
Let x, x+2 & x+4 be the 3 odd integers.
x(x+2)=(x+4)^2-34
x^2+2x=x^2+8x+16-34
x^2-x^2+2x-8x=-18
-6x=-18
x=-18/-6
x=3 ans. for the smallest integer.
3=2=5 ans. for the middle integer.
3+4=7 ans. for the ;aegest integer.
Proof:
3*5=7^2-34
15=49-34
15=15