SOLUTION: Find and label the vertex and the line of symmentry and graph the function, f(x)=5x^2. Type in ordered pairs.

Algebra ->  Graphs -> SOLUTION: Find and label the vertex and the line of symmentry and graph the function, f(x)=5x^2. Type in ordered pairs.      Log On


   



Question 310681: Find and label the vertex and the line of symmentry and graph the function, f(x)=5x^2. Type in ordered pairs.
Answer by nyc_function(2741) About Me  (Show Source):
You can put this solution on YOUR website!
Let the point (x,y) = your vertex
We use x = -b/2b to find x.
Let x = line of symmetry
Let a = 5 (the number in front of x^2) and b = 0 since there is no be term.
x = -(0)/2(5)
x = 0/10
x = 0....This is your line of symmetry. This line evenly divides the parabola formed by the function f(x) = 5x^2 on the xy-plane.
To find your vertex, replace x with 0 in your function and solve for y.
But, where is y?
We can write y as f(x) or vice-versa. They both mean the same thing.
y = 5(0)^2
y = 5(0)
y = 0
Your vertex is the point (0,0). This parabola opens UPWARD and has a minimum point at the origin, which is represented by (0,0).
Understand?