Question 310668: Solve the following oblique triangles
1. a=23.47, b=115 degrees, 30', and c=20 degrees, 29'.
2. a=134.2, b=84.54, and B=52 degrees, 9 minutes, 11 seconds.
3. a=627.7, b=412.2, and A=66 degrees, 47'.
i knows its alot but anyones help will be appreciated
Thank you :D
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Solve the following oblique triangles
1. a=23.47, B=115 degrees, 30', and C=20 degrees, 29'.
Angle A = 180-(B + C)
Then use the Law of Sines to find b, and c
b/sin(B) = a/sin(A)
c/sin(C) = a/sin(A)
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2. a=134.2, b=84.54, and B=52 degrees, 9 minutes, 11 seconds.
Find angle "A" using the Law of Sines:
sin(A)/a = sin(B)/b
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Then angle C = 180-(A + B)
Then use Law of Sines to find c:
c/sin(C) = b/sin(B)
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3. a=627.7, b=412.2, and A=66 degrees, 47'.
Can you now handle this one?
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Cheers,
Stan H.
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