SOLUTION: if Theta is an angle between 0 degrees and 90 degrees such that sin=3/5, how much is sec?

Algebra ->  Trigonometry-basics -> SOLUTION: if Theta is an angle between 0 degrees and 90 degrees such that sin=3/5, how much is sec?      Log On


   



Question 310628: if Theta is an angle between 0 degrees and 90 degrees such that sin=3/5, how much is sec?
Found 2 solutions by stanbon, Fombitz:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
if Theta is an angle between 0 degrees and 90 degrees such that sin=3/5, how much is sec?
----------------
sin = y/r
---
If sin = 3/5, y = 3 and r = 5
---
Then x = sqrt(r^2-y^2) = sqrt(25-9) = 4
---
sec = r/x
So, sec = 5/4
======================
Cheers,
Stan H.

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Find the cos.
(sin)^2+(cos)^2=1
(3/5)^2+(cos)^2=1
(cos)^2=1-9/25
(cos)^2=16/25
cos=4/5
sec=1/cos=5/4