You can put this solution on YOUR website! (5-x)^1/2 = x + 1
Square both sides to get:
5-x = x^2+2x+1
x^2 + 3x - 4 = 0
Factor:
(x+4)(x-1) = 0
x = -4 or x = 1
---
Note: x cannot = -4
Only solution: x = 1
==========================
(3x + 2)^1/2 - (2x + 7 )^ 1/2 = 0
---
(3x+2)^(1/2) = (2x+7)^(1/2)
---
Square both sides:
3x+2 = 2x+7
x = 5
==========================
Cheers,
Stan H.
==========================
(