SOLUTION: three consecutive even intergers are such that the product of the first two is 6 less than 9 times the third. find the intergers

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Question 310419: three consecutive even intergers are such that the product of the first two is 6 less than 9 times the third. find the intergers
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
Let x, x+2 & x+4 be the 3 integers.
x(x+2)=9(x+4)-6
x^2+2x=9x+36-6
x^2+2x-9x-36+6=0
x^2-7x-30=0
(x-10)(x+3)=0
x-10=0
x=10 10+2=12 & 10+4=14 ans.
x+3=0
x=-3 -3+2=-1 & -3+4=1 ans.
Proofs:
10*12=9*14-6
120=126-6
120=120
-3*-1=9*1-6
3=9-6
3=3