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Question 31031This question is from textbook College Algebra
: Hello:
I have a question about the following problem:
2x^3-3x^2-3x-5=0
I was never showed how to solve these. The book has me VERY confused. I am trying to find a zero. For my p/q, I got (plus/minus) 1, 1/2, 5, 5/2. I cannot get any of them to = 0 when I substitute. Is my arithmetic wrong, or am I going about this the wrong way? Wouldn't the zeros be the answers?
Thanks Again,
Brad Olson
This question is from textbook College Algebra
Answer by venugopalramana(3286)   (Show Source):
You can put this solution on YOUR website! I have a question about the following problem:
2x^3-3x^2-3x-5=0
F(5/2)=2*125/8-3*25/4-3*5/2-5=(250-150-60-40)/8=0...SO 5/2 IS A ROOT
I was never showed how to solve these. The book has me VERY confused. I am trying to find a zero. For my p/q, I got (plus/minus) 1, 1/2, 5, 5/2. I cannot get any of them to = 0 when I substitute. Is my arithmetic wrong, or am I going about this the wrong way?
SO 5/2 IS A ROOT CHECK YOUR ARITHMATIC...NOW DIVIDE WITH X-5/2 FIND THE QUOTIENT WHICH IS A QUADRATIC ,USE THE QUADRATIC FORMULA IF NEEDED TO FIND THE FACTORS.
Wouldn't the zeros be the answers?
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