SOLUTION: How many 7 card hands having exactly 3 Aces, 4 other cards can be dealt? Five coins are tossed. Find the Probability of each event. a. At least one comes up tails.

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Question 310248: How many 7 card hands having exactly 3 Aces, 4 other cards can be dealt?

Five coins are tossed. Find the Probability of each event.
a. At least one comes up tails.


b. Exactly two come up tails


Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
How many 7 card hands having exactly 3 Aces, 4 other cards can be dealt?
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# of ways to get 3 Aces: 4C3 = 4
# of ways to get 4 other cards = 48C4
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# of 7 card hands with 3 aces and 4 other cards: 4*48C4 = 778,320
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Five coins are tossed. Find the Probability of each event.
a. At least one comes up tails.
P(at least one) = 1 - P(no tails)
= 1 - (1/2)^5
= 1-1/32
= 31/32
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b. Exactly two come up tails
P(2 tails) = 5C2(1/2)^2(1/2)^3 = 5C2/32 = 10/32 = 5/16
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cheers,
Stan H.