SOLUTION: find three consecutive even integers such that the product of the second and third integers is twenty more than ten times the first integer

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Question 309869: find three consecutive even integers such that the product of the second and third integers is twenty more than ten times the first integer
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
Let the 3 even integers be: x, x+2 & x+4
(x+2)(x+4)=10x+20
x^2+6x+8-10x-20=0
x^2-4x-12=0
(x-6)(x+2)=0
x-6=0
x=6 ans.
Proof:
(6+2)(6+4)=10*6+20
8*10=60+20
80=80
x+2=0
x=-2 ans.
Proof:
(-2+2)(-2+4)=10*-2+20
0*2=-20+20
0=0