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Question 309784: the slope is parallel to the following equation " y=-2/3x+5 " and goes through the following ordered pair (6,-7) what is the slope and the equation please show your work and explination.
the equation is perpindicular to the following equation " y=-2/3x+5 " and goes through the following ordered pair (6,-7) what is the slope and the equation please show your work and explination.
Answer by checkley77(12844)   (Show Source):
You can put this solution on YOUR website! y=-2/3x+5 " and goes through the following ordered pair (6,-7) what is the slope and the equation please show your work and explination.
Any paralllel line will have the same slope. Thus the slope of the line through (6,-7) is =-2/3.
Y=mX+b where m=the slope & b=the Y intercept.
Using the slope & the X & Y points (6,-7) we need to solve for b
-7=-2/3*6+b
-7=-12/3+b
b=-7+4
b=-3 the Y intercept.
Thus this line equation is:
Y=-2X/3+3
 (graph 300x200 pixels, x from -6 to 8, y from -10 to 10, -2x +3).
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perpendicular to the following equation " y=-2/3x+5 " and goes through the following ordered pair (6,-7) what is the slope and the equation
A perpendicular line will have a slope equal to the negative reciprical of the line it is perpendicular to.
Thus this line will have a slope=3/2 or 1.5
-7=3/2*6+b
-7=18/2+b
b=-7-9
b=-16 ans for the Y intercept.
Y=1.5x-16
 (graph 300x200 pixels, x from -6 to 8, y from -20 to 10, 1.5x -16).
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