SOLUTION: find three positive numbers whose sum is 44 if the second number is twice the first and the third number is two thirds the first.

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Question 309617: find three positive numbers whose sum is 44 if the second number is twice the first and the third number is two thirds the first.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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find three positive numbers whose sum is 44 if the second number is twice the
first and the third number is two thirds the first.
:
x + y + z = 44
:
"the second number is twice the first"
y = 2x
:
"the third number is two thirds the first."
z = 2%2F3x
:
Replace y and z in the 1st equation, find x:
x + 2x + 2%2F3x = 44
3x + 2%2F3x = 44
multiply both sides by 3, results:
9x + 2x = 3(44)
11x = 132
x = 132%2F11
x = 12
then
y = 2(12)
y = 24
and
z = 2%2F3(12)
z = 8
:
:
Check solution: 12 + 24 + 8 = 44