SOLUTION: What is the product of the numerators when 4/8 and 8/10 are written in lowest terms? (A) 2 (B) 4 (C) 8 (D) 16 (E) 32

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: What is the product of the numerators when 4/8 and 8/10 are written in lowest terms? (A) 2 (B) 4 (C) 8 (D) 16 (E) 32      Log On


   

Question 309572: What is the product of the numerators when 4/8 and 8/10 are written in lowest
terms?
(A) 2 (B) 4 (C) 8 (D) 16 (E) 32
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
What is the product of the numerators when 4/8 and 8/10 are written in lowest
terms?
(A) 2 (B) 4 (C) 8 (D) 16 (E) 32
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The product of the numerators is 32.
(4/8)*(8/10) = 32/80
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After reduction = 2/5
A 2
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It's a poorly worded problem. The numerator of the product in lowest terms is 2.
The "product of the numerators" is still 32.